Acetophenone xrightarrow{{HCO_3H}} A xrightar | vedclass

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(C) $1$. $Acetophenone$ $(C_6H_5COCH_3)$ undergoes $Baeyer-Villiger$ oxidation with peroxy acid $(HCO_3H)$ to form phenyl acetate ($A$,$C_6H_5OCOCH_3$

Vedclass · Accepted Answer

$	ext{PhOH} 	ext{ & } 	ext{Phenolphthalein}$

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(C) $1$. $Acetophenone$ $(C_6H_5COCH_3)$ undergoes $Baeyer-Villiger$ oxidation with peroxy acid $(HCO_3H)$ to form phenyl acetate ($A$,$C_6H_5OCOCH_3$).$2$. Acid-catalyzed hydrolysis $(H_3O^{+})$ of phenyl acetate yields phenol ($C$,$C_6H_5OH$) and acetic acid ($B$,$CH_3COOH$).$3$. Phenol $(C)$ reacts with phthalic anhydride in the presence of $H^{+}$ to form phenolphthalein $(D)$,which acts as an indicator.$4$. Thus,$C$ is phenol $(PhOH)$ and $D$ is phenolphthalein.

$Acetophenone$ $\xrightarrow{{HCO_3H}} A$ $\xrightarrow{{H_3O^{+}}} B + C$ $\mathop {\xrightarrow{{Phthalic \, Anhydride}}}\limits_{{H^{+}}} $ Indicator $(D)$
$C$ and $D$ are

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$Acetophenone$ $\xrightarrow{{HCO_3H}} A$ $\xrightarrow{{H_3O^{+}}} B + C$ $\mathop {\xrightarrow{{Phthalic \, Anhydride}}}\limits_{{H^{+}}} $ Indicator $(D)$$C$ and $D$ are